CAD CAM EDM DRO - Yahoo Group Archive

Re: [CAD_CAM_EDM_DRO] explanation needed

Posted by Harvey White
on 2003-09-14 19:42:26 UTC
On Sun, 14 Sep 2003 20:38:01 -0000, you wrote:

>what is meant by the following ...........
>
>" sinking XX ma "
>
>boy do i have a lot to learn !

If current goes into the chip, then you are "sinking" the current....
If current flows out of the chip, you are "sourcing" the current.

TTL logic is very good at sinking current.. as an average TTL load
(standard variety) is 1.6 ma sink, and about 40 ua (microamps)
sourcing... as far as the chip driving the load is concerned... (it's
a back biased diode in behavior...)

So asking a TTL gate (specified for 10 loads capacity... called
"fanout" to run an LED (which can take 5 to 10 ma)... is possible only
if the current from the LED goes to the gate output... (read printer
port....)....

That is possible only if there is a separate 5 volt supply, current
goes through a resistor (to limit current)... thence to the LED (or
"input" of an optoisolator)... then through the gate to ground.

THe most that a TTL gate could source would be about 1 ma or so
(milliamps...) and that's not good enough....

Sourcing the current would mean that the LED cathode is grounded, the
gate goes to the Anode (+) lead, through a resistor...

Hope that this gives you an idea....

Harvey


>
>don

Discussion Thread

Don Thigpen 2003-09-14 19:11:36 UTC explanation needed Harvey White 2003-09-14 19:42:26 UTC Re: [CAD_CAM_EDM_DRO] explanation needed Bevan Weiss 2003-09-14 21:27:46 UTC Re: explanation needed Jon Elson 2003-09-14 22:24:10 UTC Re: [CAD_CAM_EDM_DRO] explanation needed Don Thigpen 2003-09-15 07:40:46 UTC Re: explanation needed