Re: [CAD_CAM_EDM_DRO] Polar Coordinate based CNC

Since Y=rsin(theta) and X=rcos(theta) it is a very simple conversion. If
you want to go the other way it becomes: r=sqrt(x^2+y^2) and
theta=arctan(y/x).

Should be a simple conversion. The problem is how do you do a linearly
interpolated move from one point to another? Do you even want to do linear
moves in polar coordinate space?

Daniel J. Statman, Statman Designs
www.statmandesigns.com
dan.statman@...

----- Original Message -----
From: "Alan Marconett KM6VV" <KM6VV@...>
To: <CAD_CAM_EDM_DRO@yahoogroups.com>
Sent: Saturday, November 02, 2002 3:02 PM
Subject: Re: [CAD_CAM_EDM_DRO] Polar Coordinate based CNC


> Hi Lee,
>
> Sounds like this would be similar to a Rho-Theta arm. Yes, the
> controller would have to know how to convert rectangular to polar
> coordinates. I'm wondering if EMC can already do this? That would be
> WILD machine!
>
> Alan KM6VV
>