Re: stepper encoders
Posted by
jeffalanp
on 2002-12-02 15:16:54 UTC
--- In CAD_CAM_EDM_DRO@y..., JanRwl@A... wrote:
<snip>
> inverted inputs, and I suppose some might be configured to "want"
both, but I
> can't imagine why!
>
</snip>
The reason why an encoder circuit would "want" both A and A# is
for data integrity. Lets assume that A is LOW (thus A# is HIGH).
Just sitting there everything is OK. Now a voltage spike is
introduced into the system (somehow). This could raise the A from a
voltage equating to LOW to just over the threshold where is gets
detected as a HIGH (BAD). If the A# is also included, it will also
get the spike and its voltage will raise as well. Now, rather than
just checking the voltage of the line, we compare the A and A#. If A
is greater than A# we can say the level is HIGH. If A# is greater
than A we say the level is LOW. A voltage spike introduced won't
change the way the two signals compare to one another, it will just
raise their respective voltage levels.
Jeff
www.xylotex.com
Discussion Thread
mmiami johnson
2002-12-02 10:15:46 UTC
stepper encoders
caudlet
2002-12-02 10:51:51 UTC
Re: stepper encoders
Art
2002-12-02 12:22:05 UTC
Re: [CAD_CAM_EDM_DRO] stepper encoders
JanRwl@A...
2002-12-02 14:58:17 UTC
Re: [CAD_CAM_EDM_DRO] stepper encoders
jeffalanp
2002-12-02 15:16:31 UTC
Re: stepper encoders
jeffalanp
2002-12-02 15:16:54 UTC
Re: stepper encoders
Bob Simon
2002-12-02 15:24:56 UTC
Re: [CAD_CAM_EDM_DRO] stepper encoders
JanRwl@A...
2002-12-02 17:43:48 UTC
Re: [CAD_CAM_EDM_DRO] Re: stepper encoders
Ray Henry
2002-12-03 06:22:08 UTC
Re: stepper encoders