Re: [CAD_CAM_EDM_DRO] Re: What is Rms?
Posted by
Jon Elson
on 2005-11-26 14:36:28 UTC
turbulatordude wrote:
for sine waves, only, and will give incorrect AC readings on anything other
than a sine wave. Duty cycle can be used simply to calculate the average
voltage or current. But, if a square wave voltage is applied to a resistive
device, the power delivered will not match the duty cycle * voltage. That
is because power is volts X amps. When the voltage goes up, the current
ALSO goes up, by the same factor. Therefore, a change in voltage causes
a change in power equal to the SQUARE of the change in voltage. This is the
whole key to the thing.
So, if you were to apply 120 V DC to a 120 Ohm resistor, it would draw
one amp, and dissipate 120 Watts. If you applied 240 V 50% of the time,
it would draw 2 A, and dissipate 480 W during the on time, and of course
zero during the off time. The average power dissipation would be 240 W
(480 / 2). So, although the average VOLTAGE is the same 240/2 = 120,
the average POWER is twice as large, in this example.
Jon
>I was under the impression that RMS only applied to sine wave typeNo, RMS can apply to any waveform. Ordinary voltmeters are corrected
>power (or half wave) but not to square wave. After all, isn't duty
>cycle used to calculate current ?
>
>
>
for sine waves, only, and will give incorrect AC readings on anything other
than a sine wave. Duty cycle can be used simply to calculate the average
voltage or current. But, if a square wave voltage is applied to a resistive
device, the power delivered will not match the duty cycle * voltage. That
is because power is volts X amps. When the voltage goes up, the current
ALSO goes up, by the same factor. Therefore, a change in voltage causes
a change in power equal to the SQUARE of the change in voltage. This is the
whole key to the thing.
So, if you were to apply 120 V DC to a 120 Ohm resistor, it would draw
one amp, and dissipate 120 Watts. If you applied 240 V 50% of the time,
it would draw 2 A, and dissipate 480 W during the on time, and of course
zero during the off time. The average power dissipation would be 240 W
(480 / 2). So, although the average VOLTAGE is the same 240/2 = 120,
the average POWER is twice as large, in this example.
Jon
Discussion Thread
robertokx
2005-11-23 23:49:48 UTC
What is Rms?
Stephen Wille Padnos
2005-11-24 00:14:14 UTC
Re: [CAD_CAM_EDM_DRO] What is Rms?
turbulatordude
2005-11-24 08:36:08 UTC
Re: What is Rms?
Graham Stabler
2005-11-24 12:10:57 UTC
Re: What is Rms?
Andy Wander
2005-11-25 13:27:21 UTC
RE: [CAD_CAM_EDM_DRO] Re: What is Rms?
turbulatordude
2005-11-25 15:07:21 UTC
Re: What is Rms?
juan gelt
2005-11-25 16:53:18 UTC
Re: [CAD_CAM_EDM_DRO] Re: What is Rms?
Joel Hagen
2005-11-25 23:06:21 UTC
Re: What is Rms?
Joel Hagen
2005-11-25 23:06:47 UTC
Re: What is Rms?
Stephen Wille Padnos
2005-11-26 07:38:52 UTC
Re: [CAD_CAM_EDM_DRO] Re: What is Rms?
turbulatordude
2005-11-26 09:12:19 UTC
Re: What is Rms?
Jon Elson
2005-11-26 14:36:28 UTC
Re: [CAD_CAM_EDM_DRO] Re: What is Rms?
Andy Wander
2005-11-26 15:30:03 UTC
RE: [CAD_CAM_EDM_DRO] Re: What is Rms?
turbulatordude
2005-11-27 09:45:28 UTC
Re: What is Rms?
Jon Elson
2005-11-27 10:24:22 UTC
Re: [CAD_CAM_EDM_DRO] Re: What is Rms?
Graham Stabler
2005-11-27 16:46:32 UTC
Re: What is Rms?
Andy Wander
2005-11-27 16:55:24 UTC
RE: [CAD_CAM_EDM_DRO] Re: What is Rms?
Andy Wander
2005-11-27 17:00:08 UTC
RE: [CAD_CAM_EDM_DRO] Re: What is Rms?
Graham Stabler
2005-11-28 07:40:55 UTC
Re: What is Rms?