Re: [CAD_CAM_EDM_DRO] Electrical Help
Posted by
Tony Jeffree
on 2000-08-06 00:53:31 UTC
At 20:15 05/08/00 -0500, you wrote:
dropped across each resistor is the same as the ratio of the resistor values.
Regards,
Tony
>This is not correct. If you have some voltage Vin, and you have aMy apologies - what I should have said is that the ratio of the voltages
>resistor, R1
>connected to Vin and Vout, and another resistor R2 connected from Vout
>to
>ground, then the equation is Vout = Vin * (R2 / (R1 + R2)). So, it is
>not a simple
>ratio. If the resistors are of equal value, then the output will be one
>half of the
>input.
>
>(The explanation is that the dividing ratio is that of the load (R2)
>resistance to
>the entire resistor chain (R1 + R2).)
dropped across each resistor is the same as the ratio of the resistor values.
Regards,
Tony
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Re: [CAD_CAM_EDM_DRO] Electrical Help