Re: [CAD_CAM_EDM_DRO] Electrical Help

Tony Jeffree wrote:

> At 14:27 04/08/00 -0500, you wrote:
> >Please define "Voltage divider network"
>
> Stick 2 resistors in series across the voltage source; the voltage at
> the
> junction of the two resistors is the source voltage reduced by the
> ratio of
> the two resistor values. If both resistors have the same value, the
> voltage at the junction is half the source voltage....etc.

This is not correct. If you have some voltage Vin, and you have a
resistor, R1
connected to Vin and Vout, and another resistor R2 connected from Vout
to
ground, then the equation is Vout = Vin * (R2 / (R1 + R2)). So, it is
not a simple
ratio. If the resistors are of equal value, then the output will be one
half of the
input.

(The explanation is that the dividing ratio is that of the load (R2)
resistance to
the entire resistor chain (R1 + R2).)

Jon