Re: More on servo motor selection

Drew,

I think you are confusing something here. Gearing cannot change
power, only the mix of torque and speed.

Your motor is 60 in-oz at 2600 RPM, or 115 Watts. If you used 10:1
reduction you would have 600 in-oz at 260 RPM, which is still 115
Watts.

Mariss

> Hi all,
>
> I did some more thinking about what I expect from the little CNC

mill

> I'd like to play with and I think that a .100" deep full width cut

with

> a .500" dia. endmill at 30 ipm seems to be a resonable max. That cut
> removes .1 x .5 x 30 = 1.5 cu. in. of material per minute. At Jon's
> suggested rate of 3 cu. in. per hp for aluminum I need .5 hp to

sustain

> the above rate. 1 hp = 746 watts so I need 373 watts. So given

Mariss'

> calculation that, what seems to be the better motor I mentioned

earlier

> (see message #30095), can generate 60 oz. in @ 2600 rpm which equals
> about 115 watts, I need at least a 3 to 1 reduction between the

motor

> and the table. The table I'm using has a 10 pitch leadscrew so is

this

> more than enough to cover the required reduction. In other words,

does

> the leadscrew turn the 115 watts of the motor into 1150 watts? If I
> do add say a 2 to 1 reduction between the motor and the leadscrew do
> I now have over 3000 watts? With a 2 to 1 reduction @ 2600 rpm I can
> still run the table at 130 ipm which seems plenty to me right now.
>
> So how does all this sound? Am I way off in left field confusing

electrical

> hp with mechanical hp?
>
> Jon E., could you explain the process of computing the forces at the
> table for computing the
> Drew Rogge
> drew@p...