Re: Quadrature divider circuit?
Posted by
dakota8833 <dakota8833@b...
on 2003-02-21 17:47:46 UTC
--- In CAD_CAM_EDM_DRO@yahoogroups.com, "Bernard R <bwjarandall@c...>"
<bwjarandall@c...> wrote:
is the wrong term. Just two IC's (7490's ) per encoder, nothing else.
Will divide by 2 , 5 ,or 10 . Cost me 4.99 a three pack at the local
electronics store
Sure beats $ 120.00 for 3 new encoders
Let you know how it works Mon.
Frank ,....
<bwjarandall@c...> wrote:
> Hi All,Funny you should ask ,... this weekend I wiring one up. Well wiring up
>
> To save re-inventing the wheel, does anyone have a circuit to reduce
> the quadrature signals from an encoder. I am looking for a divide by
> 2 or possibly div 4.
>
> Thanks
>
> Bernard R
is the wrong term. Just two IC's (7490's ) per encoder, nothing else.
Will divide by 2 , 5 ,or 10 . Cost me 4.99 a three pack at the local
electronics store
Sure beats $ 120.00 for 3 new encoders
Let you know how it works Mon.
Frank ,....
Discussion Thread
Bernard R <bwjarandall@c...
2003-02-20 06:38:50 UTC
Quadrature divider circuit?
dakota8833 <dakota8833@b...
2003-02-21 17:47:46 UTC
Re: Quadrature divider circuit?
Bernard R <bwjarandall@c...
2003-02-21 19:57:33 UTC
Re: Quadrature divider circuit?
Larry Edington
2003-02-21 21:59:00 UTC
Re: [CAD_CAM_EDM_DRO] Re: Quadrature divider circuit?
Bernard R <bwjarandall@c...
2003-02-21 22:49:21 UTC
Re: Quadrature divider circuit?
dakota8833 <dakota8833@b...
2003-02-23 20:50:47 UTC
Re: Quadrature divider circuit?