Re: Proper pull up resistors for optical limits

The wiring diagram shows the resistor on the output side where the
+5V comes off the connector pin (#4) on the servo amp,... it shows
the resistor between the +5V output and the optical interrupter,
then from the optical interrupter it goes back to the isolated
ground on the connector on the servo amp (pin #6). The other side
of the interrupter gets connected to limit in pin (#5) and then to
the isolated ground (#6).

On the optical switch: Pin 1= Anode, Pin 2= Cathode, Pin 3=
Collector, and Pin 4= Emitter. I'm unsure which gets connected to
+5V, Ground, and Limit in, but I'm hoping there will be some
instructions with the switch. I'm very newbee to all of this.

Hope that helps to make it a little clearer on what size resistor I
need. Thanks

Frank

--- In CAD_CAM_EDM_DRO@yahoogroups.com, "Roy J. Tellason"
<rtellason@b...> wrote:

> On Thursday 13 May 2004 10:16 pm, fun2b432002 wrote:
>
> > They show a resistor between the +5V and the optical interrupter

switch but

> > do not give a value on the resistor.
>
> That's probably because the correct value for the resistor depends

on the opto

> device...
>
> > I assume this is a pullup resistor (I know very little about

this) and I'm

> > wondering if anyone can help me with determining which size

resistor to

> > use????
>
> Sure.
>
> > The optical switches are transistor output type, Min Output 0.5

IC @ 20 mA

> > IF. Another type I may use are the same except Min Output 1.8

IC @ 20 mA

> > IF.
>
> I'm a little unclear here -- are you talking about connecting the

resistor on

> the input side or on the output side?