Re: Unipolar as bipolar.
Posted by
Alan Marconett KM6VV
on 2000-10-06 15:52:50 UTC
Mariss,
Then your white paper was only talking about "series" connection of BOTH
coils being good for 1/2 power? There must still be some drawbacks.
Nothing's for free! You still have twice inductance, compared to being
allowed to parallel connect the coils. So I suspect there is still
considerable power drop-off at higher speeds? The motor would be
limited by it's inductive reactance earlier then the parallel
connection. Still worthwhile.
Alan
Mariss Freimanis wrote:
Then your white paper was only talking about "series" connection of BOTH
coils being good for 1/2 power? There must still be some drawbacks.
Nothing's for free! You still have twice inductance, compared to being
allowed to parallel connect the coils. So I suspect there is still
considerable power drop-off at higher speeds? The motor would be
limited by it's inductive reactance earlier then the parallel
connection. Still worthwhile.
Alan
Mariss Freimanis wrote:
>
> Alan,
>
> It is counter-intuitive, but here's the reason:
>
> A step motor reaches its rated power at the corner frequency. The
> corner frequency is where the motor's inductive reactance begins to
> limit current and not the drive.
>
> Beyond that speed, inductive current (I = V / 2 pi f L) drops rapidly
> with speed and I squared R losses drop even more rapidly.
>
> The main effect of using only 50% of the copper is the winding
> resistance is twice as high. This "extra" resistance develops a
> voltage drop that subtracts from the voltage the motor "sees".
>
> This voltage drop becomes insignificant (<3%) because of the
> diminishing inductive current at higher speeds.
>
> Since motor output power is proportional to supply voltage, this 3%
> voltage drop results in a 3% power drop.
>
> At low speeds there is no performance penalty at all because torque
> is proportional to current, and it is the drive that sets the current.
>
> Dyno tests bear this out.
>
> Example: a 3V, 4A unipolar motor would be the same as a 1.5V, 4A
> parallel wired 8-wire motor. The difference is 1.5V. If this motor
> were run at 60VDC, the first motor would see 57V (60-3) while the 2nd
> motor would see 58.5V (60-1.5). The ratio would be 57/58.5 or 97.4%
> the power of a parallel wired motor.
>
> Mariss
>
> --- In CAD_CAM_EDM_DRO@egroups.com, Alan Marconett KM6VV <KM6VV@a...>
> wrote:
> > Thanks Mariss,
> >
> > I wasn't aware that only using 1/2 the winding would be that close
> to a
> > parallel connection. The old Slo-Syn tables I have don't look that
> > good. More like 20%, as I recall. Still, you waste 1/2 the
> windings!
> >
> > Alan
Discussion Thread
J. J. Larsen
2000-10-06 09:19:25 UTC
Unipolar as bipolar.
Kevin P. Martin
2000-10-06 10:11:08 UTC
RE: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Dan Mauch
2000-10-06 10:41:28 UTC
Re: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 11:46:42 UTC
Re: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Mariss Freimanis
2000-10-06 13:36:20 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 14:01:49 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 15:13:04 UTC
Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-06 15:30:24 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 15:52:50 UTC
Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-06 16:43:44 UTC
Re: Unipolar as bipolar.
Jon Elson
2000-10-06 22:00:51 UTC
Re: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Ron Ginger
2000-10-10 13:08:03 UTC
Re: [CAD_CAM_EDM_DRO] Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-10 17:51:39 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-10 18:15:56 UTC
Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-10 18:47:24 UTC
Re: Unipolar as bipolar.