Re: Unipolar as bipolar.
Posted by
Mariss Freimanis
on 2000-10-10 17:51:39 UTC
Ron,
You are correct that motor torque is proportional to ampere-turns.
The concept that operates here is that current flowing into a node
must equal the current flowing out. In the case of a bi-filar winding
(two parallel paths), it doesn't matter how the current gets
apportioned, equally or otherwise. The same total current passes thru
the same number of turns of wire.
Always there is theory and there is empirical testing of theory. The
latter is the judge as to whether a theory is the true reflection of
nature or just a pretty construct. It is the final arbiter of truth.
In this case dyno testing bears out theory. The difference in results
(about 3%) is exactly accounted for as due to the greater resistance
losses of a single winding.
You can't fool mother nature; she always sets you straight, often
humbling you in the process. If you're smart you learn.
Mariss
You are correct that motor torque is proportional to ampere-turns.
The concept that operates here is that current flowing into a node
must equal the current flowing out. In the case of a bi-filar winding
(two parallel paths), it doesn't matter how the current gets
apportioned, equally or otherwise. The same total current passes thru
the same number of turns of wire.
Always there is theory and there is empirical testing of theory. The
latter is the judge as to whether a theory is the true reflection of
nature or just a pretty construct. It is the final arbiter of truth.
In this case dyno testing bears out theory. The difference in results
(about 3%) is exactly accounted for as due to the greater resistance
losses of a single winding.
You can't fool mother nature; she always sets you straight, often
humbling you in the process. If you're smart you learn.
Mariss
>schoool,
> Ok, but I recall from my old electric motor class (tech high
> pre- 1960) that motor 'strength' had a lot to do with AMP-TURNS, soif I
> have 2 windings, both of the same turns count, and both carryingthese
> current, dont I get twice the magnetic field? Obviously if your
> 'stranded wire' analogy above is correct then I dont, but since
> wires are insulted from ecah other then we have 'different amps'flowing
> through each coil.
>
> ron
Discussion Thread
J. J. Larsen
2000-10-06 09:19:25 UTC
Unipolar as bipolar.
Kevin P. Martin
2000-10-06 10:11:08 UTC
RE: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Dan Mauch
2000-10-06 10:41:28 UTC
Re: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 11:46:42 UTC
Re: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Mariss Freimanis
2000-10-06 13:36:20 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 14:01:49 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 15:13:04 UTC
Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-06 15:30:24 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-06 15:52:50 UTC
Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-06 16:43:44 UTC
Re: Unipolar as bipolar.
Jon Elson
2000-10-06 22:00:51 UTC
Re: [CAD_CAM_EDM_DRO] Unipolar as bipolar.
Ron Ginger
2000-10-10 13:08:03 UTC
Re: [CAD_CAM_EDM_DRO] Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-10 17:51:39 UTC
Re: Unipolar as bipolar.
Alan Marconett KM6VV
2000-10-10 18:15:56 UTC
Re: Unipolar as bipolar.
Mariss Freimanis
2000-10-10 18:47:24 UTC
Re: Unipolar as bipolar.