Re: [CAD_CAM_EDM_DRO] TTL questions
Posted by
Jon Elson
on 2001-03-22 11:45:35 UTC
Marcus & Eva wrote:
TTL and LS logic chips have asymmetrical output current capabilites.
They can sink (pull to ground) much more current than they can source
(pull to +5 V). So, in many cases where you need a greater current pulling
up to +5V, or a faster rise time, you connect a resistor to +5V, to supply
that additional current.
Jon
> >Don't confuse a "pull-UP" resistor with a "series resistor".Whew! Sounds like we will get a censor if you keep saying things like that!
>
> Hi All:
> What on earth is a "pull-up" resistor???
> Sounds like ( in the immortal words of my lovely wife) those situations in
> the morning where she's trying desperately to pull up her underwear and I've
> got my hands in the way!!
TTL and LS logic chips have asymmetrical output current capabilites.
They can sink (pull to ground) much more current than they can source
(pull to +5 V). So, in many cases where you need a greater current pulling
up to +5V, or a faster rise time, you connect a resistor to +5V, to supply
that additional current.
Jon
Discussion Thread
Doug Harrison
2001-03-19 15:40:01 UTC
TTL questions
Jon Elson
2001-03-19 16:10:43 UTC
Re: [CAD_CAM_EDM_DRO] TTL questions
Doug Harrison
2001-03-19 19:24:22 UTC
Re: [CAD_CAM_EDM_DRO] TTL questions
JanRwl@A...
2001-03-21 12:08:35 UTC
Re: [CAD_CAM_EDM_DRO] TTL questions
Marcus & Eva
2001-03-22 08:16:43 UTC
Re: [CAD_CAM_EDM_DRO] TTL questions
Jon Elson
2001-03-22 11:45:35 UTC
Re: [CAD_CAM_EDM_DRO] TTL questions
JanRwl@A...
2001-03-22 15:19:29 UTC
Re: [CAD_CAM_EDM_DRO] TTL questions
JanRwl@A...
2001-03-22 15:20:17 UTC
Re: [CAD_CAM_EDM_DRO] TTL questions