RE: [CAD_CAM_EDM_DRO] Bipolar stepper driver for unipolar steppers

Chris:

While I understand that the voltage drop of the motors would double because
of the increased winding resistance, I don't understand why the current
would halve IF the motors were driven by a constant current source. Would
you not maintain the same current as long as the open circuit voltage could
support it and take advantage of increased torque? I realize that this
increase would come at the expense of top speed due to the inductance, as
you mention. Could you explain a little bit more?

-- Carol & Jerry Jankura
Strongsville, Ohio
So many toys, so little time....

|It is very hard for a drive to pump
|current through the inducatance of a 13.4v rated coil at a fast
|switching speed for high rpm operation. So you will probably get
|better performance using just half of each coil (tape up the extra
|leads) and setting the driver for the rated winding current.
|
|Chris