RE: [CAD_CAM_EDM_DRO] need torque formula help

It's a ratio. FX:

Hammer: 12/1*12*force.12 inches from force to fulcrum divided by 1 inch from
fulcrum to nail times length of lever times force

Crowbar: 12/3*12*force.12 inches from force to fulcrum divided by 3 inches
from fulcrum to nail times length of lever times force



Hammer 12/1*12*25 lbs=3600 Lbs force under the nail

Crowbar 12/3*12*25 lbs=1200 Lbs force under the nail

R. Wink

From: CAD_CAM_EDM_DRO@yahoogroups.com
[mailto:CAD_CAM_EDM_DRO@yahoogroups.com] On Behalf Of turbulatordude
Sent: Sunday, November 20, 2011 10:09 AM
To: CAD_CAM_EDM_DRO@yahoogroups.com
Subject: [CAD_CAM_EDM_DRO] need torque formula help





Hi all,

looking for the formula, not the answer so much.

if you have a hammer to pull a nail, the claw is, say, 1 inch from the nail.

if you use a crowbar, the claw is 3 inches.

The handle is 1 foot in both cases.

What I am trying to determine is the pulling action at the nail.

what has me stumped is that the simple formula, F=weight x distance does not
offer the offset.

can I just use the hypotenuse to calculate force ?

Thanks!

Dave



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