Re: need torque formula help

Thanks,.

I was having trouble visualizing this.

since the fulcrum is the right angle. in loose terms, force on one side is proportional to force on the other.

I was not doing the second operation from the fulcrum to the 'nail'

Thanks R.Wink and Roland. you guys made it simple for me.

Dave

--- In CAD_CAM_EDM_DRO@yahoogroups.com, "rwwink" <rwwink@...> wrote:
>
> It's a ratio. FX:
>
> Hammer: 12/1*12*force.12 inches from force to fulcrum divided by 1 inch from
> fulcrum to nail times length of lever times force
>
> Crowbar: 12/3*12*force.12 inches from force to fulcrum divided by 3 inches
> from fulcrum to nail times length of lever times force
>
>
>
> Hammer 12/1*12*25 lbs=3600 Lbs force under the nail
>
> Crowbar 12/3*12*25 lbs=1200 Lbs force under the nail
>
> R. Wink
>
> From: CAD_CAM_EDM_DRO@yahoogroups.com
> [mailto:CAD_CAM_EDM_DRO@yahoogroups.com] On Behalf Of turbulatordude
> Sent: Sunday, November 20, 2011 10:09 AM
> To: CAD_CAM_EDM_DRO@yahoogroups.com
> Subject: [CAD_CAM_EDM_DRO] need torque formula help
>
>
>
>
>
> Hi all,
>
> looking for the formula, not the answer so much.
>
> if you have a hammer to pull a nail, the claw is, say, 1 inch from the nail.
>
> if you use a crowbar, the claw is 3 inches.
>
> The handle is 1 foot in both cases.
>
> What I am trying to determine is the pulling action at the nail.
>
> what has me stumped is that the simple formula, F=weight x distance does not
> offer the offset.
>
> can I just use the hypotenuse to calculate force ?
>
> Thanks!
>
> Dave
>
>
>
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Thanks,.

I was having trouble vusualizing this.

since the fulcrum is the right angle. in loose terms, force on one side is proportional to force on the other.


I was not doing the second calculation from the fulcrum to the 'nail'

Thanks !