Re: [CAD_CAM_EDM_DRO] Re: stepper current

> Wouldn't dissipation be increased by a factor of four rather than a factor
> of two? If I remember correctly, power varies as the square of the current
> rather than as the current (P = V*I; V=IR; so P = I^2 * R)

Only if the resistance stays constant, which it doesn't - it doubles
when you go from half coil to full. Another way to look at it - you
put the same current in with twice the voltage, so the power doubles.

Chris

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Christopher C. Stratton, stratton@...
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