Re: Question about angular and linear feedrates

Hi Brian,

Yes, I can understand that! I'm thinking if the cut radius on the
rotary table is other then about 1" dia, THEN I must adjust my
called-out feedrate.

Or for those writing controllers, considering the addition of a radius
parm? Maybe use of the alternate radius form of G02/G03 would be useful
here? Maybe THAT's why they did it?

I'm comfortable knowing that I'll get about the same feedrate on my
hardware at 1" dia; and other then that, I'll adjust the feedrate as
required (this assumes that the 'A' axis (on my hardware/software) is
the fastest moving... I.E., needs the most steps to complete it's move.
Otherwise, the 'A' axis feedrate will be SLOWER then the other axis.

This may or may not "industry standard". But it gives me a starting
point.

Alan KM6VV


superintendent_god_botherer2000 wrote:

>
> Hi Alan
>
> but the part program isnt using a radius value
> the 'A' move is called out in degrees so those are the
> units it should use for the velocity interpolation
>
> I would rather have the control do what its told
> instead of letting it assume anything (we all know what
> happens when you assume something ;-)
>
> Brian
>
> --- In CAD_CAM_EDM_DRO@y..., Alan Marconett KM6VV <KM6VV@a...> wrote:
> > Hi Brian,
> >
> > Well instead of 0, why not have it assume a radius that gives the
> same
> > feedrate, I.E. with my 3.6" /rev equivalent feed, a 1" dia gives
> nearly
> > (1.14159", actually) the same feedrate. I haven't tested this!
> But I'm
> > thinking then even with out a "radius" parm, it would be a simple
> mental
> > exercise to double or halve (or whatever) the feedrate to adjust for
> > other dia's.
> >
> > Alan KM6VV
>
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