Re: [CAD_CAM_EDM_DRO] Re: Confused over My own Calculations!
Posted by
Jon Elson
on 2002-08-18 20:33:07 UTC
William Scalione wrote:
the current limit setpoint. If it didn't do that, the motor would burn up.
When the transistors are on for 100% of the time the motor phase should
be polarized that direction, then the current and torque start to drop.
(current change, min to max) and a low DC power supply voltage, so current
dropped after the motor reached a modest speed.
Jon
> On Sunday 18 August 2002 01:59 pm, Jon wrote:Because the stepper driver shuts off the voltage when the current rises to
>
> >
> > Now, this is ONLY at idle, and will vary due to the design of the motors
> > and drivers. When the motor is producing substantial torque at some
> > speed, the power drawn will increase dramatically, and therefore the
> > current mist also rise. But, the peak power may occur only during
> > acceleration, and therefore be transient. So, you should not need a power
> > supply rated for continuous output of 8 A per motor in the above example.
> > Probably 4 A/motor would work in most cases, except where you know all
> > motors would be accelerating simultaneously.
> >
> > Jon
> >
>
> Jon, or anyone else
>
> This is just to satisfy my curiosity as I'm running servos and really don't
> ever plan on using steppers again. The servo performance is so much better.
>
> Anyway, we always talk about raising the voltage on a stepper system to
> overcome the inductance in a stepper motor's windings. It would seem that at
> a high step rate the voltage will not be building up to the max that the
> power supply can deliver, and since the resistance of the windings will not
> change, why wouldn't the current be more when the motor was not turning.
the current limit setpoint. If it didn't do that, the motor would burn up.
>That the driver adjusts the on-time of the transistors to limit the current.
> At idle the voltage will have had plenty of time to raise to the max level
> and and hence, using ohms law the full current that can be delivered by the
> drive should be flowing. But at speed the voltage will be lower and it seems
> as though the current should also be lower. What am I missing here
When the transistors are on for 100% of the time the motor phase should
be polarized that direction, then the current and torque start to drop.
> I know a few years back while running a stepper system with a chopper driveThat drive probably had a slow on-off cycle, thereby causing a lot of Delta-I
> the motors would get hot as hell while standing still but cool down
> considerably when running. Obviously there was no current reduction on that
> drive.
(current change, min to max) and a low DC power supply voltage, so current
dropped after the motor reached a modest speed.
Jon
Discussion Thread
mayfieldtm
2002-08-17 13:42:20 UTC
Confused over Mariss's Calculations
mayfieldtm
2002-08-17 14:07:25 UTC
Confused over My own Calculations!
turbulatordude
2002-08-17 20:03:03 UTC
Re: Confused over My own Calculations!
mayfieldtm
2002-08-18 00:03:06 UTC
Re: Confused over My own Calculations!
Jon Elson
2002-08-18 10:52:54 UTC
Re: [CAD_CAM_EDM_DRO] Re: Confused over My own Calculations!
mayfieldtm
2002-08-18 13:24:06 UTC
Re: Confused over My own Calculations!
Jon Elson
2002-08-18 13:39:03 UTC
Re: [CAD_CAM_EDM_DRO] Re: Confused over My own Calculations!
mariss92705
2002-08-18 17:07:03 UTC
Re: Confused over My own Calculations!
William Scalione
2002-08-18 17:49:23 UTC
Re: [CAD_CAM_EDM_DRO] Re: Confused over My own Calculations!
mariss92705
2002-08-18 18:36:41 UTC
Re: Confused over My own Calculations!
Jon Elson
2002-08-18 20:33:07 UTC
Re: [CAD_CAM_EDM_DRO] Re: Confused over My own Calculations!
William Scalione
2002-08-19 00:35:56 UTC
Re: [CAD_CAM_EDM_DRO] Re: Confused over My own Calculations!
turbulatordude
2002-08-19 06:11:38 UTC
8 wire steppers ( was Re: Confused over My own Calculations!