where's the torque ?

I've been running thru the torque numbers for motors and seem to be
missing something.

A 1-1/2hp treadmill motor with 5,100 RPM has 296 oz-in torque.

On a rack and pinion. and using a 1.25" pitch, we can round the
distance per gear rotation to 4 inches. 1.25*pi=3.926, so 4 is close
enough.

When we calculate for a leadscrew, we come back to inches of table
movement. do we also do that for routers ?

I mean that we put on a 600oz-in motor, then multiply that by 5TPI to
get 3,000 OZ-IN that would mean 3,000 per inch, no ?

That would make the motor 296/4=74 oz-in if it were direct drive.
using 6:1 pulleys would then multiply that up to 444 oz-in. or 444 per
inch ?

The leadscrew moves 1 inch per 5 motor rev or 0.2" per rev while the
rack moves 1.5 revs per in. Gearing up to get 5 rev's per inch would
mean a 20:1 pulley to the 1:4 rack gear. If course that would
multiply the 296 by 5 for 1,482oz-in.

Since I've seen routers and plasma cutter run with much smaller motors
and much smaller ratios (3:1 on a 350 oz-in stepper) it seems I'm
missing something.

Anyone see my mistakes or what I've overlooked ?

Dave