Re: [CAD_CAM_EDM_DRO] Re: Question? UCN5804

Just for reference, the calculation is "Product over Sum" for resistors in
parallel. Multiply all the individual resistors by one another (works of
they are all alike or not) and then divide that number by the sum value of
all the resistors.

That's memory from 10 years ago at Penn State, hopefully my memory still is
correct.

R. William Kichman, P.E.
Kichman Engineering Associates
103 Old Furnace Road
Cornwall, PA 17016-0643
tel/fax 717/270-0714

----- Original Message -----
From: "turbulatordude" <davemucha@...>
To: <CAD_CAM_EDM_DRO@yahoogroups.com>
Sent: Wednesday, July 02, 2003 11:21 PM
Subject: [CAD_CAM_EDM_DRO] Re: Question? UCN5804


> --- In CAD_CAM_EDM_DRO@yahoogroups.com, chrlythb@a... wrote:
> > Dave,
> >
> > Couldn't they use 20 100K 1/4 watt resistors?
>
> 20 of the 1/4 watt in parallel would offer the 5 watts
>
> 20 of the 100k would be a 5K total at 5 watts.
>
> 20 total resistors to make a 1k circuit would need to be 20 of the
> 20k resistors.
>
> Assuming that one were off to RS to get some such 'fix' it would be
> smart to get what prices out the best. if 1/4 watt were cheaper, and
> in stock, then that would be the best.
>
> Dave
>
>
>
> >
> > Charlie B
>
>
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