CAD CAM EDM DRO - Yahoo Group Archive

Re: Reduction by 10

Posted by vavaroutsos
on 2003-10-17 09:11:10 UTC
Neither, the circumference of a circle is equal to Pi * D where D is
the diameter. Therefore the reduction ratio is equal to the ratio of
the diameters. So 5/2 = 2.5:1 reduction, 2/1 = 2:1 reduction. The
combination of 5":2":1" would provide a total of 5:1 reduction (2.5 *
2).

~petev

--- In CAD_CAM_EDM_DRO@yahoogroups.com, ccq@x wrote:
> On timing belt setups, does a reduction of 10 requier a 5" wheel
driven by a 2"
> wheel, or would it be 5":2":1"?
>
> Bill
>
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Discussion Thread

washcomp 2003-10-16 07:17:31 UTC Control Pendant/Panel layout for your comments wanliker@a... 2003-10-16 07:44:44 UTC Re: [CAD_CAM_EDM_DRO] Control Pendant/Panel layout for your comments washcomp 2003-10-16 16:05:32 UTC Re: Control Pendant/Panel layout for your comments wanliker@a... 2003-10-16 18:02:25 UTC Re: [CAD_CAM_EDM_DRO] Re: Control Pendant/Panel layout for your comments washcomp 2003-10-16 23:41:37 UTC Re: Control Pendant/Panel layout for your comments wanliker@a... 2003-10-16 23:47:00 UTC Re: [CAD_CAM_EDM_DRO] Re: Control Pendant/Panel layout for your comments ccq@x... 2003-10-17 04:37:48 UTC Reduction by 10 vavaroutsos 2003-10-17 09:11:10 UTC Re: Reduction by 10 ccq@x... 2003-10-17 11:05:17 UTC Re: [CAD_CAM_EDM_DRO] Re: Reduction by 10 Torsten 2003-10-17 12:13:01 UTC Re: Reduction by 10 ccq@x... 2003-10-17 14:26:03 UTC Re: [CAD_CAM_EDM_DRO] Re: Reduction by 10 caudlet 2003-10-17 16:39:07 UTC Re: Control Pendant/Panel layout for your comments Raymond Heckert 2003-10-17 20:00:02 UTC Re: [CAD_CAM_EDM_DRO] Re: Reduction by 10 washcomp 2003-10-17 20:00:38 UTC Re: Control Pendant/Panel layout for your comments