Re: [CAD_CAM_EDM_DRO] Re: Reduction by 10

Yup, If you wants 10 : 1 in two steps, yer needs a 5 : 1 feeding a 2 : 1.
Better yet, a 4 : 1 feeding a 5 : 2 (always more efficient, when ratios are
close, and use a large enough wheel for the smallest one). Doesn't matter
if you're talking diameters, or teeth.

RayHex

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> From: ccq@...
>
> Huh? Lets try this again. First off, I was refering to diameters to

start

> with, just didn't specify it I guess. The idea is to get 10 turns in to

1 turn

> out, a reduction of 10, without having to use an enormous 10" diameter

wheel to

> do it. Are we on the same page, so far?
>
> On Fri Oct 17 09:11:08 2003 vavaroutsos wrote:
>
> >Neither, the circumference of a circle is equal to Pi * D where D is
> >the diameter. Therefore the reduction ratio is equal to the ratio of
> >the diameters. So 5/2 = 2.5:1 reduction, 2/1 = 2:1 reduction. The
> >combination of 5":2":1" would provide a total of 5:1 reduction (2.5 *
> >2).