Re: [CAD_CAM_EDM_DRO] Re: Reduction by 10

Huh? Lets try this again. First off, I was refering to diameters to start
with, just didn't specify it I guess. The idea is to get 10 turns in to 1 turn
out, a reduction of 10, without having to use an enormous 10" diameter wheel to
do it. Are we on the same page, so far?

On Fri Oct 17 09:11:08 2003 vavaroutsos wrote:

>Neither, the circumference of a circle is equal to Pi * D where D is
>the diameter. Therefore the reduction ratio is equal to the ratio of
>the diameters. So 5/2 = 2.5:1 reduction, 2/1 = 2:1 reduction. The
>combination of 5":2":1" would provide a total of 5:1 reduction (2.5 *
>2).
>
>~petev
>
>--- In CAD_CAM_EDM_DRO@yahoogroups.com, ccq@x wrote:
>> On timing belt setups, does a reduction of 10 requier a 5" wheel
>driven by a 2"
>> wheel, or would it be 5":2":1"?

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