Re: [CAD_CAM_EDM_DRO] Frozen stepper motor shaft

It does Andy.. you really had me worried there
for a bit.. Here I'd spent all that time getting
everything just so, only to think that It was all
wrong! Oh well.. doc say's it's good to get your
heart rate up once in a while :-)

Jarrett

----- Original Message -----
From: "Andy Wander" <awander@...>
To: <CAD_CAM_EDM_DRO@yahoogroups.com>
Sent: Sunday, January 22, 2006 1:15 PM
Subject: RE: [CAD_CAM_EDM_DRO] Frozen stepper
motor shaft


> Jarrett!
>
> You've got it! You just don't know it. I am not
> saying that you multiply
> oz-in by anything. I am saying that you GET
> oz-in by multiplying. That's
> what makes it oz-in or "ounces times inches".
>
> Once you know oz-in, you DIVID by the distance
> in inches to get the
> force in ounces.
>
> You can only do that BECAUSE oz-in is gotten by
> multiplying distance in
> inches by force in ounces to get oz-in.
>
> oz-in
> -------- = oz
> in
>
> Or in english, "ounce inches, divided by inches,
> give you ounces".
>
> You don't multiply ONCE YOU HAVE ounce inches.
> You multiply to GET ounce
> inches.
>
> Hope this helps.
>
> Andy Wander
>
> -----Original Message-----
> From: CAD_CAM_EDM_DRO@yahoogroups.com
> [mailto:CAD_CAM_EDM_DRO@yahoogroups.com] On
> Behalf Of Jarrett & Heidi
> Johnson
> Sent: Sunday, January 22, 2006 1:55 PM
> To: CAD_CAM_EDM_DRO@yahoogroups.com
> Subject: Re: [CAD_CAM_EDM_DRO] Frozen stepper
> motor shaft
>
> I don't intend to dispute, just to clarify in my
> own mind.
>
> When I use oz-in to calculate my torque from my
> stepper I multiply?
> This seems in reverse to me.
> I'm planning on using a 640 oz-in stepper. Now
> my gearing from this
> stepper is a via timing belt.
> So.. the pulley attached to my stepper is 1.910
> Pitch Dia. so the ARM
> of this pully would be the radius at which the
> belt is located or:
> 1.910/2 =0.955" So if I have a 640 oz-in
> stepper this would equate to
> 640*0.955"=611.2 oz force at that arm distance?
> So if instead I was to
> put my larger pulley on the stepper [ this
> wouldn't work because I'm
> trying to gear down but for sake of
> discussion]it's a 3.820 Pitch Dia.
> so...
> 3.820/2=1.91" arm then we put this into this
> same formulat 640 oz-in *
> 1.91"=1222.4 oz force. It would seem that this
> is exactly backwards to
> how it works, we all go get a long[er] pipe to
> put on a wrench to get
> more ARM distance and get more torque at the
> bolt. If this is infact the
> correct way to calculate this stuff then I've
> not been doing my
> calulations all wrong and my system isn't going
> to budge when I go to
> run it.
>
> Anyway in my mind this oz-in thing should
> involve division. 640 oz-in
> means there is 640 oz of force located at 1"
> from the center of the
> stepper shaft. I don't think anyone disputes
> this. If the arm was 1/2"
> then 640 oz-in/ 0.50"= 1280 oz force you'd cross
> off the inch's because
> it's inches divided by inches and you'd be left
> with only 'oz' unit's.
> If you multiplied this equation you'd be left
> with oz-in^2. or at least
> this is how I see it.
>
> Help!
> Jarrett
>
>
>
>
>> Alan:
>>
>> Yes, I have brought it up before. Some will say
>> I am too picky(I guess
>
>> you are one of them) but it is NOT a division,
>> it is a multiplication,
>
>> that becomes the "unit". If you look into WHY
>> we use "ounce inches" or
>
>> similar terms for torque, you will quickly
>> understand why(1 oz-in of
>> torque equates to a 1 ounce force at an inch
>> from the center of
>> rotation, but to only 1/2 ounce of force at 2
>> inches from the center
>> of rotation-do the math-you MULTIPLY the ounce
>> by the inches).
>>
>> If you ever start trying to use these units in
>> a mathematical
>> formula(which is not that far out a
>> proposition, considering we are
>> attempting to design and build machines that
>> use
>> torque) you will get
>> hopelessly confused, as the units won't
>> "cancel"
>> properly.
>>
>> The worst part is, that the folks who KNOW it
>> is "ounce-inches", and
>> not "ounces per inch", and can shrug off the
>> improper use, won't get
>> caught, because they KNOW how to use the
>> formulas and calculations.
>> But those who DON'T know the proper terminology
>> are the ones who most
>> likely won't be able to make sense out of it.
>>
>> That's why I think it is important, and will
>> keep bringing it up, as
>> long as I think it is important.
>>
>> Back to the subject at hand, I think your
>> advice to do an ohmmeter
>> check on the windings was good, as was that of
>> the other poster who
>> recommended making sure none of the leads were
>> touching when trying to
>
>> turn the motors. Until Mike gets back to us on
>> what else he has tried,
>
>> I don't think we can go much further in solving
>> his problem, unless it
>
>> would be to recommend that he checks the shafts
>> where theey exit the
>> bearings and motor case for any evidence of
>> corrosion. If they are
>> rusted or pitted to the point where that is
>> what is causing sticking,
>> theen a good penetrating oil might do the
>> truick.
>>
>> Andy Wander
>> Verrex Corporation
>>
>> P.S. By the way, I am sure that you know that
>> just because a Google
>> search turns up a bunch of mistakes, that
>> doesn't make them suddenly
>> become correct.
>
>
>
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