RE: [CAD_CAM_EDM_DRO] Plasma table gear reduction

Dave,

I understand the 1000 rpm for calculation purposes, but I would go for as
low
a servo rpm as is practicable to minimize the gear/belt ratio. Low rpm ,
low inertia, High torque.

Example: A 500 oz in servo directly driving a 1" pinion or timing gear
would give 100 ipm at 31.8 rpm with 1000 oz (62.5 lbf) and so on.

This might not be enough force, but you get the idea...just using bigger
torquey motors and drives is often cheaper that futzing around with
high ratio transmissions.

Looking back from the rack or belt the moment of inertia of the servo
armature
will be the SQUARE of the drive ratio....100 times with 10:1.

Yes I agree beyond 3 or 4 to one a jackshaft would be in order. I would
also consider low backlash gears.

-----Original Message-----
From: turbulatordude [mailto:dave_mucha@...]
Sent: Sunday, December 19, 2004 1:30 PM
To: CAD_CAM_EDM_DRO@yahoogroups.com
Subject: [CAD_CAM_EDM_DRO] Plasma table gear reduction




Hi all,

Next step is the transmission.

Assuming a 1,000 RPM servo motor (for ease of calculations)

and a rack or belt drive.

It would appear that the lowest gear ratio is about 1:1 and that is
using a pretty small drive gear.

Assuming one wants 100 inch per min speeds, there is a need for a
10:1 reduction.

I can get a pair of timing belt pulleys for about a 3:1, maybe a 4:1,
and that would indicate that a jackshaft would be in order for two
sets of belt reduction.

This seems pretty striaght forward and different pulleys offer the
ability to change ratios.

Obvously, when the surplus motors are spinning 4 times faster, it
means the need for a reduction is required.

Is there a simplier way to do reduction ?

Dave








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