Re: Declining motor torque with lower voltage.

> If you need 1000 Pounds of linear force (cutting force + friction +
> acceleration)
> then 1000 *0.0318 = 31.8 In-Lb, or 508 In-Oz. That would presumably be
> the PEAK torque requirement for X and Y on a mill. But, it could be
> close to this
> as the CONTINUOUS torque on the knee, unless you had a counterbalance
> system.
>
> In the above examlple, if you had a 250 Oz-In peak torque motor, then
> you'd want a
> 2:1 belt reduction ratio, at the minimum.
>
> Jon

So Jon, what your are saying is that I could direct couple my 600
oz-in (peak) servo's and they would produce 1000+ lbs of linear force
on my Bridgeport. And 1000 lbs is a good value to be at for the
X and Y axis. I would also then get 240 ipm rapids.
Am I correct? Everyone seems to be using a lot more power to the
table than this.

Scott