Re: [CAD_CAM_EDM_DRO] Sinosidal Encoder signals to TTL signals converter

juan gelt wrote:

>i'm glad it helped you. good thing you are already
>familiar with the linear encoders.
>you said: 'you'd get a voltage swing from zero to 11
>uA.'
>

No, I just looked, I said you'd get a voltage swing from
zero to 11 milli-VOLTS.

>things like this which may seem self evident to you,
>already knowing the technical data, WILL be obscure to
>ppl who aren't and confusing to ppl who measure
>voltages with Volts and current with Amps.
>after your 'explanation' there is still insufficient
>information (for me). this is my own deficiency,
>certainly.
>volts pp at 11uA would be really nice to know.
>

This conversion is made with Ohm's law, in the form :
Volts = Amps/resistance

So, if you divide 11 uAmps by 1000 Ohms, you get
.000011 Amp /1000 Ohm= .011 Volt, or 11 mV.
If you desire a different voltage, you use a different resistor
value.

>knowing is it full quadrature would be rather
>necessary if one intends to decode step/dir signals.
>a resistor and a comparator isn't the whole job, if i
>understood what little i did correctly.
>

Actually, it takes two identical copies of the same circuit,
to convert the two quadrature sine waves to two quadrature
square waves. You feed one of the sine signals to each comparator,
and you get two digital (square wave) signals out.

>
>

Jon