Re: [CAD_CAM_EDM_DRO] RE: Cam track help!

Since I cannot leave a mathematical problem alone, I have compared the two
sets of data. Your data represents a 45 degree phase shift of the sine wave
and a 0.34 inch axial shift (half of the peak to peak wave height). When
the data are plotted on the same scale and the phase shift and offset are
taken into account they are IDENTICAL.

The way I determined this was to plot both sets of data and look at the
differences, it is obvious once that is done.

Daniel J. Statman, Statman Designs
www.statmandesigns.com

----- Original Message -----
From: "j.guenther" <j.guenther@...>
To: <CAD_CAM_EDM_DRO@yahoogroups.com>
Sent: Wednesday, August 21, 2002 3:15 PM
Subject: RE: [CAD_CAM_EDM_DRO] RE: Cam track help!


> Dan,
>
> That's fine with me, take your time. I have no idea where he set the
origin
> either, I will try to scan the information I have and email it to you off
> list. I read the article last night and it does not give any information
on
> how he calculated the sine wave for the track. It might be in his patent
> application, I will search for that tonight if I get a chance. I was not
> questioning the formula, just the difference in results which I assumed
was
> a difference in origin points.
>
> I am beginning to under stand why Brayton Paul had a shop in Ohio cut the
> tracks for the 10 sets of castings he made. He had no CNC capability and
> had attempted to cut them using a bell crank mechanism driven off the lead
> screw on his lathe with a Sherline lathe head mounted to the cross slide
to
> drive a milling cutter. He stated in the article that this did not work
out
> so he found a shop to cut them for him. I am convinced that the cam track
> can be cut using CNC and a rotary table to a reasonably high degree of
> accuracy.
>
> I am going to build a mach up of this thing just to see the motion. The
> piston rotates on a splined shaft while the track converts the linear
motion
> of the piston to rotary motion of the crank shaft.
>